A charge Q = 8.90 times 101-04 C is distributed uniformly along a rod of length

Question

A charge Q = 8.90 times 101-04 C is distributed uniformly along a rod of length 2L, extending from y = -22.2 cm to y = +22.2 cm, as shown in the diagram above. A charge q = 7.80 times 10-06 C, and the same sign as Q, is placed at (D,0), where D = 73.0 cm. Consider the situation as described above and the following statements. If the statement is true, answer "T, if it is false, answer F, and if the answer cannot be determined from the information provided, answer C'. For example if 'B' and C' are true and there is not enough information to answer D' and the rest are false, then answer FTTCF. The net force on q in the x-direction equals zero. The total force on q is in the northeast direction. The charge on a segment of the rod of infinitesimal length dy is given by dQ=(Q/2L)dy The net force on q in the y-direction does not equal zero. The magnitude of the force on charge q due to the small segment dy is dF=(kqQ/4Lr*r)dy

Explanation / Answer

T T F T T

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