A. 3 GUUUACUGAAC \'5 B. 3 CAAAUGACUUG 5 C. 5\' CAAAUGACUUG 3 D. 5\' GUUCAGUAAAC

Question

A. 3 GUUUACUGAAC '5 B. 3 CAAAUGACUUG 5 C. 5' CAAAUGACUUG 3 D. 5' GUUCAGUAAAC 3 3. During Translation, the .. scans the mRNA for a start codon. Once a start codon is recognized, theis then recrulted which actually carries out the process of putting together the polypeptide chain. A. RNA Polymerase, Ribosome B. Small Ribosomal Subunit, Large Ribosomal Subunit C. Helicase, Ligase D. RNA polymerase, tRNA 4. The Protein "Stoutase" is 114 base paits long and is responsible for proper DNA cleavage. Which of the following would cause the most detrimental effect on the protein? A. A missense mutation in base pair 65 B. A nonsense mutation in base pair 113 C. A nonsense mutation in base pair 65 D. A silent mutation in base pair 3 5. Also considering the protein mentioned above, what is the most likely effect on DNA cleavage if a nonsense mutation leads to a change in amino acid from a Serine to a stop in base pair 80 A. DNA cleavage will proceed as usual B. DNA cleavage will mostly stop but may still proceed slightly C. DNA cleavage will mostly function properly but may proceed slightly slower than usual D. DNA cleavage will stop ew Sec 1 Pages 1 of 3 Words: 121 of 649L

Explanation / Answer

3) The correct answer is option B that is small ribosomal unit and, larger ribosomal unit because small ribosomal subunit scans the mRNA first to start the translation and then after recognizing the AUG it recruits large ribosomal subunit.

4) The correct answer is option C that is nonsense mutation in base pair 65. In nonsense mutation a change in nucleotide causes a stop codon and because of that truncated protein is formed and that is the most detrimental mutation.

Missense mutation just change one amino acid so that won't affect protein that much. So, option A is wrong and nonsense mutation in base pair 113 won't make any difference because last three base pairs are supposed to be the stop codon and if 113 that is second last base makes a stop codon by mutation, then that won't make any difference. So, option B is wrong too.

Silent mutation doesn't make any difference so option D is wrong too.

5) DNA cleavage will stop ia the correct answer that is option D because if the stop codon is formed earlier than the truncated protein will be formed and because of that no proper 3D structure is formed and without 3 D structure, protein can't function.

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