Figure 29-50 shows a particle with positive charge q = 4.80 x 10-19 C moving wit

Question

Figure 29-50 shows a particle with positive charge q = 4.80 x 10-19 C moving with speed v = 7.68 x 105 m/s toward a long straight wire with current i = 365 mA. At the instant shown, the particle's distance from the wire is d = 1.03 cm. What is the magnitude of the force on the particle due to the current?

Figure 29-50 shows a particle with positive charge q = 4.80 x 10-19 C moving with speed v = 7.68 x 105 m/s toward a long straight wire with current i = 365 mA. At the instant shown, the particle's distance from the wire is d = 1.03 cm. What is the magnitude of the force on the particle due to the current?

Explanation / Answer

B=0i/2d

F=qv x B

=4.8*10-19*7.68*105 * 2 * 10- 7 *0.365/0.0103=5.44 *4.8*10-19

=2.61*10-18N

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