For one approach to this problem, consult Interactive LearningWare 24.1. For eac

Question

For one approach to this problem, consult Interactive LearningWare 24.1. For each of the three sheets of polarizing material shown in the drawing, the orientation of the transmission axis is labeled relative to the vertical. The incident beam of light is unpolarized and has an intensity of 1750 W/m2. What is the intensity of the beam transmitted through the three sheets when theta 1 = 16.7 degree, theta 2 = 52. 9 degree, and theta 3 = 105 degree? The number of significant digits is set to 3; the tolerance is +/-2%

Explanation / Answer

I = (1750) * (1/2) * (cos2(52.9-16.7)) * (cos^2(105-52.9))

= (1750) * (1/2) * 0.65118 * 0.377346

= 215 W/m2

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