A solid sphere of radius R and mass M is held against a wall by a string being p
ID: 2149284 • Letter: A
Question
A solid sphere of radius R and mass M is
held against a wall by a string being pulled at
an angle . f is the magnitude of the frictional
force and W = M g .
a)To what does the torque equation
about point O (the center of the sphere) lead?
1. F+W= f
2. W= f
3. Fsin(theta)= f
4. F=f
5. Fsin(theta)cos(theta)= f
b)To what does the vertical component of the
force equation lead?
1. Fcos(theta)+W=f
2. Fsin(theta)=f
3. Fsin(theta)+f=W
c)Find the smallest coefficient of friction ?
needed for the wall to keep the sphere from
slipping.
1. u=tan(theta)
2. u=cos(theta)
3. u=1/tan(theta)
4. u=sin(theta)
5. u=1/cos(theta)
6. u=1/sin(theta)
I know this is long, but I've worked on every part and I keep getting the answer wrong. I know it's a lot to ask, but I really need this problem explained.
Explanation / Answer
a)F is trying to rotate it clockwise, so the friction force will try to rotate it anticlockwise and will act upward.
Balancing moments,
F.r=f.r
F=f
4) is correct.
b)This is pretty obvious.
3. Fsin(theta)+f=W
c)The normal force on the wall be N.
Balancing horizontal forces,
N=FCos
f=N=FCos
From a)
f=F
FCos=F
=1/Cos
5) is correct.
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.