A croquet ball weighing 8.6 N is travelling at 2.3 N. For how long of a time int

Question

A croquet ball weighing 8.6 N is travelling at 2.3 N. For how long of a time interval must a force of 4.5 N be applied to this object I n order to stop it. 0.270 N 0.449 N 0.876 N 1.125 N 3.742 N a bullet of mass 0.3 g is travelling at 1275 m/s when it embeds into a piece of wood (mass = 18g) which is initially at rest on a frozen lake. Take mu s = mu k = 0.28 for the ice- wood interface. Ignore air resistance. What is the instantaneous velocity of the wooden block after being hit by the bullet? 0.2 m/s 23.3 m/s 357.0 m/s 1275 m/s 20.9 m/s

Explanation / Answer

First we need to find the deceleration of the ball

Apply the formula F = ma

m = 8.6/9.8 (since they gave us the weight of the ball, and we need the mass)

m = .878 kg

Now F = ma

(4.5) = (.878)a

a = 5.13 m/s2

Now that we have the deceleration, and we know that the ball will come to a stop, we can apply

vf = vo + at   (a will be negative since it is a deceleration)

0 = 2.3 + (-5.13)t

t = .449 sec

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