Please help i have no idea how to do this! Thanks. A 1260 N uniform beam is atta
ID: 2145391 • Letter: P
Question
Please help i have no idea how to do this! Thanks.
A 1260 N uniform beam is attached to a vertical wall at one end and is supported by a cable at the other end. A W = 1810 N crate hangs from the far end of the beam. (a) Calculate the magnitude of the horizontal component of the force that the wall exerts on the left end of the beam.(b) Calculate the magnitude of the vertical component of the force that the wall exerts on the left end of the beam.
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A 1260 N uniform beam is attached to a vertical wall at one end and is supported by a cable at the other end. A W = 1810 N crate hangs from the far end of the beam. (a) Calculate the magnitude of the horizontal component of the force that the wall exerts on the left end of the beam.(b) Calculate the magnitude of the vertical component of the force that the wall exerts on the left end of the beam.Explanation / Answer
a)
T = sin50*(1810+(sin30*1260))= 1869.148 N
The weight of the hanging mass plus the vertical component of the weight of the beam, times sin50 gives the Tension component
b)
horizontal:
cos30 * 1260 = 1091.192 N
vertical:
sin30 * 1260 = 630 N
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