A conical pendulum is formed by attaching a 0.70 kg ball to a 1.0 m long string,

Question

A conical pendulum is formed by attaching a 0.70 kg ball to a 1.0 m long string, then allowing the mass to move in a horizontal circle of radius 30 cm the figure show that the string traces out the surface of a cone, hence the name.

What is the tension in the string?

What is the ball's angular velocity, in rpm?

A conical pendulum is formed by attaching a 0.70 kg ball to a 1.0 m long string, then allowing the mass to move in a horizontal circle of radius 30 cm the figure show that the string traces out the surface of a cone, hence the name. What is the tension in the string? What is the ball's angular velocity, in rpm?

Explanation / Answer

here eqn of motion is Tcos? -mg = 0

from diagram sin?=r/l =0.3/1=0.3

?=17.45 deg

a.T= mg/cos?

T= 0.7*9.8/cos17.45

T=7.19N

b.time periodT=2pi sqrt(lcos17.45)/g

T =2pi(0.312)

w= 2pi/T = 2pi/2pi(0.312)

w=3.205 rad/sec

w= 3.205*60/2pi

w= 30.62 rpm

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