A conical pendulum is formed by attaching a 0.90kg ball to a 1.0m -long string,

Question

A conical pendulum is formed by attaching a 0.90kg ball to a 1.0m -long string, then allowing the mass to move in a horizontal circle of radius 40cm. The figure (Figure 1) shows that the string traces out the surface of a cone, hence the name.

What is the tension of the string?

What is the ball's angular velocity, in rpm?

A conical pendulum is formed by attaching a 0.90kg ball to a 1.0m -long string, then allowing the mass to move in a horizontal circle of radius 40cm. The figure (Figure 1) shows that the string traces out the surface of a cone, hence the name. What is the tension of the string? What is the ball's angular velocity, in rpm?

Explanation / Answer

The question is expecting ypou to see how the centrifugal force balances the gravitation force. forece-out = mass * velocity^2 /radius force-down = mass * g (where g=10/s/s) The pendulum makes angle A with the vertical where sin A = 30 / 100 force-out * sin A = tension = force-down * cos A When you understand this, you can plug in the numbers to find tension and then the velocity. Finally revs/sec = velocity/(2 pi *radius)

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