A tow truck pulls a car 5.50 km along a horizontal roadway using a cable having

Question

A tow truck pulls a car 5.50 km along a horizontal roadway using a cable having a tension of 810 N.

A tow truck pulls a car 5.50 km along a horizontal roadway using a cable having a tension of 810 N. How much work does the cable do on the car if it pulls horizontally? How much work does the cable do on the car if it pulls at 32.5 degree above the horizontal? How much work does the cable do on the tow truck if it pulls the car horizontally? How much work does the cable do on the tow truck if it pulls the car at 32.5 degree above the horizontal? How much work does gravity do on the car in part (a) if its pulled horizontally? How much work does gravity do on the car in part (a) of its pulled at an angle of 32.5 degree?

Explanation / Answer

A)

d= 5.5 km, F= 810 N.
the equation for work is:
W= F * d cos(angle) [ F times d ]
for first one, it pulls horizontally. so, the angle between surface and the force is zero. so,

W = 810 * 5.5 = 4455 Joules

for Cable, it pulls at 32.5 degree. so,
W = 810 * 5.5 * cos(32.5) = 3757.31 Joules

B)

W = 810 * 5.5 = 4455 Joules

for Cable, it pulls at 32.5 degree. so,
W = 810 * 5.5 * cos(32.5) = 3757.31 Joules

C)

the weight of the truck.
Force of tension/ g = weight.

work done gravity, you have to multiply it by 9.8.

therefore forceof tension= work done by gravity=810N

for angle 32.5 degree

(810/9.8)*9.8cos32.5= 683.14

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