I am studying for my physics exam tomorrow afternoon, and I am coming across the

Question

I am studying for my physics exam tomorrow afternoon, and I am coming across the same equation for "t" (time) while solving...I'll give some examples, but my question is - which equation would I know to use/get this equation for "t"??

t = sq root (2 * y initial/g)

I have used this for these problems...

1. A cat is sitting on a desk 1.2 meters above the floor. A mouse runs out from under the desk in a straight line at a speed of 1.5 m/s. If the cat leaps parallel at a speed of 4.0 m/s, how much time would the jump take? ----> 0.5 seconds

2. A 10 lb cat leaps H from a 3.1 m high roof w/ a speed of 12 mph. Disregard AR. How long will the flight time be? ----> 0.8 seconds

I guess my questions are....are we getting this equation from time from the equation
(x = x initial + v initial * time + (1/2)at sq)?

and where is the 2 (inside the square root) in the equation from time coming from?

Explanation / Answer

the cat just got horizontal component of velocity while leaping .so,it doesnt matter how fast the cat leaps parallelly from table the flight time will always be sqrt(2*h/g).. as there is no vertical component of velocity ...the formula turns to be H= 0*t + 0.5*g*t^2 which gives t=sqrt(2*h/g)

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