A A 3.20 g bullet is fired horizontally at two blocks resting on a frictionless
ID: 2135908 • Letter: A
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A
A 3.20 g bullet is fired horizontally at two blocks resting on a frictionless tabletop as shown in Fig. 6-34a. The bullet passes through the first block, with mass 1.20 kg, and embeds itself in the second, with mass 1.80 kg. Speeds of 0.630 m/s and 1.40 m/s, respectively, are thereby imparted to the blocks as shown in Fig. 6-34b. Neglect the mass removed from the first block by the bullet.
A 3.20 g bullet is fired horizontally at two blocks resting on a frictionless tabletop as shown in Fig. 6-34a. The bullet passes through the first block, with mass 1.20 kg, and embeds itself in the second, with mass 1.80 kg. Speeds of 0.630 m/s and 1.40 m/s, respectively, are thereby imparted to the blocks as shown in Fig. 6-34b. Neglect the mass removed from the first block by the bullet. Find the speed of the bullet immediately after it emerges from the first block. Find the bullet's original speed.Explanation / Answer
well, moment before a collision equals total momentum ater a collison, so the bullet's initial momentum (mv) will equal the combined momentum of the blocks. There for, 3.3v= (1200*0.630)+(1800*1.40)
so, 3.3v = 756 + 2520
3.3v = 3276
v=992.73m/s < that's the answer to part (b)
To get (a) 3.3v = 2520
v = 840 m/s
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