The figure shows a cross-sectional view of two concentric, infinite length, cond

Question

The figure shows a cross-sectional view of two concentric, infinite length, conducting cylindrical shells. The inner shell has as an inner radius of a and an outer radius of b. The electric field just outside the inner shell has magnitude E0 and points radially outward as shown. The grounded, outer shell has an inner radius c and an outer radius of d. Some of the cylindrical surfaces may be charged. Let oa, ob, oc and od be the surface charge densities on the surfaces with radii a, b, c and d. There are no other charges or conductors in the problem.The surface charge density oa is zero.

Which expression correctly gives the potential, V, of the inner conducting shell?

I am completely stuck on how to solve this problem.

V = sigma b/epsilon 0a ln d/b V = sigma b/epsilon 0a ln c/b V = sigma b/epsilon 0b ln c/b V = sigma b/epsilon 0b ln d/b V = - sigma b/epsilon 0b ln c/b

Explanation / Answer

Ans:C....................if u want the solution plzzz let me know....ill post it

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