The figure shows a cross-sectional view of two concentric, infinite length, cond

Question

The figure shows a cross-sectional view of two concentric, infinite length, conducting cylindrical shells. The inner shell has as an inner radius of a and an outer radius of b. The electric field just outside the inner shell has magnitude E0 and points radially outward as shown. The grounded, outer shell has an inner radius c and an outer radius of d.

Some of the cylindrical surfaces may be charged. Let ?a, ?b, ?c and ?d be the surface charge densities on the surfaces with radii a, b, c and d. There are no other charges or conductors in the problem.

The surface charge density ?a is zero.( I know that the answer is zero but can you please explain why)

(T)   True
(F)   False

Explanation / Answer

The surface charge density a is zero. because inside a conductor there can't be any electric field hence can't exist any charge.

We can consider a point in between the inner shell then considering a Gaussian surface, then we can clearly see that the Gaussian surface must not contain any charge and the charge inside a conductor only exist at surfaces hence the charge density at innner surface must be zero.

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.