a) An aircraft flies from San Francisco to New York, a distance of 5700 km, in 5

Question

a) An aircraft flies from San Francisco to New York, a distance of 5700 km, in 5.5 h. The airspeed (speed relative to the air) of the plane is 800 km/h. How large a tailwind does the aircraft experience that day? Assuming that the airspeed and wind velocity are the same for the return flight, how long does it take to fly back to San Francisco?

b)A pilot wishes to fly from San Francisco to Sacramento, 138 km northeast. The wind is blowing from the north at 24 km/h, and the plane has an airspeed of 240 km/h. What heading must the pilot take, and how long will it take to get to Sacramento? How long would it take to get back to San Francisco assuming the same airspeed and wind velocity?

Explanation / Answer

a) Vpg = 5700/5.5=1036km/h

Vpg =Vpa+Vag

1036.36=800+Vag

Vag = 236.36 km/h
for return journey Vpg = 1036.36 - 236.36= 800kmph

time = 5700/800= 7.13hr

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