a) A solution is composed of 1.10 m o l cyclohexane ( P ? c y = 97.6 t o r r ) a

Question

a)  A solution is composed of 1.10mol  cyclohexane (P?cy=97.6 torr) and 2.60mol  acetone (P?ac=229.5 torr). What is the total vapor pressure Ptotal above this solution? Express your answer numerically in torr.


b)  the vapor above the cyclohexane-acetone solution is composed of both cyclohexane vapor and acetone vapor. What mole fraction of the vapor above the solution, Xcy(vapor), is cyclohexane? a)  A solution is composed of 1.10mol  cyclohexane (P?cy=97.6 torr) and 2.60mol  acetone (P?ac=229.5 torr). What is the total vapor pressure Ptotal above this solution? Express your answer numerically in torr.


b)  the vapor above the cyclohexane-acetone solution is composed of both cyclohexane vapor and acetone vapor. What mole fraction of the vapor above the solution, Xcy(vapor), is cyclohexane?

Explanation / Answer

p=97.6*1.10/(1.10+2.60)=29.01 torr

p=p^0(acetone)*mole fraction of acetone

= 229.5* 2.60/(1.10+2.60)

=161.27torr

total pressure= p(cyclohexane +p(acetone)

                     =161.27+29.01

=190.2torr

b)mole fraction of cyclo hexane=no,of moles of cyclo hexane/totalno.of moles

                          =1.10/(1.10+2.60)=0.29

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.