a) A square coil (not a solenoid!) has N = 3920 turns and side s = 3.59 m carrie

Question

a)A square coil (not a solenoid!) hasN=3920turns and sides=3.59m carries currentI=72.3A. Find the magnetic field at the center of the square.

NOTE: A square is four line segments.

B = _____________ T

b)Suppose a small circular coil withN=267turns, radiusr=5.75mm and carrying currentI=70.7A is placed inside the square coil from part 1 so the planes of the two coils are at right angles to each other. Assume that the magnetic field inside the small coil due to the large coil is approximately constant. Find the magnitude of the torque felt by the small coil.

?= _____________ N-m

Explanation / Answer

A) B = ( mu0 )( current ) L / [ 2( Pi)*R*sqroot(L^2 + 4R^2) ......... B=B = 4.59567e-6 T

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