A cat drops from a shelf 4.1ft above the floor and lands on all four feet. His l

Question

A cat drops from a shelf 4.1ft above the floor and lands on all four feet. His legs bring him to a stop in a distance of 12 cm.

1) Calculate his speed when he first touches the floor (ignore air resistance).

Express your answer to two significant figures and include the appropriate units.

2) Calculate how long it takes him to stop.

Express your answer to two significant figures and include the appropriate units.

3) Calculate his acceleration (assumed constant) while he is stopping, in m/s2.

Express your answer to two significant figures and include the appropriate units.

4)Calculate his acceleration (assumed constant) while he is stopping, in g

Explanation / Answer

a) vf^2=v0^2+2ad

vf^2=0+2gh or vf= sqrt[2gh]= sqrt[2*9.8m/s/s*4.1 * 0.3048] = 4.949m/s

b) once he hits the floor, his speed goes from 4.949m/s to 0, meaning the avg velocity is 2.475m/s

therefore time = dist/avg speed = 0.12m/2.475m/s = 0.0485 s

c) accel = 4.949/0.0485 = 102.04 m/s^2

d) accel = 102.04/9.8 = 10.41 g

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