A particle\'s acceleration is described by the function ax =(10-T) m/s^2 , where

Question

A particle's acceleration is described by the function ax =(10-T) m/s^2 , where t is in s. Its initial conditions are x0 = 0 m and vox = 0 m/s at t =0s. At what time is the velocity again zero? What is the particle's position at that time? Can some help me set these up?
A particle's acceleration is described by the function ax =(10-T) m/s^2 , where t is in s. Its initial conditions are x0 = 0 m and vox = 0 m/s at t =0s. At what time is the velocity again zero? What is the particle's position at that time? Can some help me set these up?

Explanation / Answer

It appears that we are dealing with linear motion of a particle, therefore I will ommit the subcript x in ax and vox for simplicity.

Acceleration: a = 10 - t

Velocity is an integral of aceleration:
v = Integral a(t) dt
v = 10t - 1/2 t

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