i need answering please .. A proton is traveling horizontally to the right at 4.

Question

i need answering please ..

A proton is traveling horizontally to the right at 4.40106 m/s

Part A

Find (a)the magnitude and (b) direction of the weakest electric field that can bring the proton uniformly to rest over a distance of 3.50 cm.

E=                                     N/C.

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Part B

?=                                        counterclockwise from the left direction.

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Part C

How much time does it take the proton to stop after entering the field?

t=                                      s.

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Part D

What minimum field ((a)magnitude and (b)direction) would be needed to stop an electron under the conditions of part (a)?

E=                                     N/C.

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Part E

?=                                counterclockwise from the left direction

   

A proton is traveling horizontally to the right at 4.40 times 106 m/s Find (a)the magnitude and (b) direction of the weakest electric field that can bring the proton uniformly to rest over a distance of 3.50 cm. E= N/C. ?= counterclockwise from the left direction What minimum field ((a)magnitude and (b)direction) would be needed to stop an electron under the conditions of part (a)? E= N/C. ?= counterclockwise from the left direction

Explanation / Answer

) A proton is traveling horizontally to the right,

Initial velocity = u = 4.4

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