A nuclear power plant generates 3000 MW of energy from nuclear reactions in reac

Question

A nuclear power plant generates 3000 MW of energy from nuclear reactions in reactor%u2019s core. This energy is used to boil water and produce high pressure steam at 340 0C. The steam spins a turbine which produces 1200 MW of electrical power. The steam is then condensed and the water is cooled to 25 0C before starting the cycle again.

A) What is the maximum thermal efficiency of the power plant?

B) What is the plant%u2019s actual efficiency?

C) Cooling water flows through a condenser (The low temperature heat exchanger) at a rate of 1.2 x 10-8 L/hr. If the water enters the heat exchanger at 18 0C, what is its exit temperature?

Explanation / Answer

Actual efficiency = Power output / Heat Input
= 1000/3000= 0.3333=33.333%
Thermal eff= 1000/ m( h300-h25)
where h is enthalpy of steam and enthalpy of feed water!

a> max eff = 1 - (273+25)/(273+340)
= 0.513
=51.3%

b> act eff = 1000/3000
= 0.333
= 33.3 %

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