A heavy sled is being pulled by two people. The coefficient of static friction b

Question

A heavy sled is being pulled by two people. The coefficient of static friction between the sled and the ground is %u03BCs = 0.579 and the kinetic friction coefficient is %u03BCk = 0.403. The combined mas of the sled and its load is m =336 kg. The ropes are separated by an angle %u03C6 = 21 degrees, and they make and angle of %u03B8 = 30.1 degrees with the horizontal. assuming both ropes pull equally hard, a) what is the minimum rope tension required to get the sled moving? and b) if the tension is maintained after the sled starts moving, what is the sled's acceleration?

Explanation / Answer

horiz force = 2Tcos31*cos10.5=1.7T

vertical comp = 2Tsin31=1.03T

friction = 0.58*(336*9.8-1.03T)=1909-.597T which must be equal to 1.7T

T = 831N

kinetic friction=0.403*(336*9.8-1.03T)=0.403*(336*9.8-1.03831)=1326.58N

acc=(1.7*831-1326.58)/336=0.256m/s2

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