A fixed coil of wire with 10 turns and an area of 0.055m^2 is placed in a perpen

Question

A fixed coil of wire with 10 turns and an area of 0.055m^2 is placed in a perpendicular magnetic field. This field oscillates in direction and magnitude at a frequency of 10Hz and has a maximum value of 0.12 T.

a) What is the average emf induced in the coil during the time it takes for the field to go from its max value in one direction to the max value in the other direction?

b) repeat part a for atime interval of one complete cycle.

c)at what time during a complete magnetic cycle would you expect the induced emf to have its max magnitude? and its minimum value?

Explanation / Answer

Part A)

EMF = -NBA/t

EMF = -(10)(.24)(.055)/(.05)

EMF = -2.64 (The negative is just sign convention - ignore it if your answer key wants you to)

Part B)
EMF = 0 V (the change in the B field in one cycle is 0)

Part C)

Max EMF is when you have gone half a turn. That is after .05 sec

Min EMF is after one complete turn. That is after .1 sec

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.