in desert regions found near the equator the intesity of solar radiation at the

Question

in desert regions found near the equator the intesity of solar radiation at the top of Earths atmoshere is about 1500 W/m^2. Assume 2/3 of this energy reaches the surface and that new generation solar panels have an eficiency of 30%. Imagine a "solar farm" that is 37 acres and a town with a population of 31,942... If tha average citizen uses 28 kw*hr per day, how many of these solar farms are needed to power the town?

Assume the farm recieves 12 hours of solar radiation per day...1 acre = 4,047m^2...

Explanation / Answer

wattage produced by the solar panels=2/3*1500*0.3*37*4047=4.5 E7 W

energy produced by 1 farm=4.5 E7*12/1000=5.4 E5 kW*hr

energy consumed by city=28*31942*24=2.14 E7 kW*hr

number of farms needed=214/5.4=40(approx)

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