in depth answer would be good. Also you cant just go F=mgsin(theta) to solve thi

Question

in depth answer would be good. Also you cant just go F=mgsin(theta) to solve this one. The only clue i have is this "The wheelbarrow must be in translational and rotational equilibrium on the inclined plank. Identify the forces that act on the wheelbarrow and their torques with respect to the pivot point, that is the wheel's axle. Note that the wheelbarrow is always parallel to the plank."

A person is pushing a uniformly-loaded 27.90 kg wheelbarrow along a plank that makes an angle alpha = 39.0 degree with the horizontal. What is the total force the person must apply so that the wheelbarrow is parallel to that plank?

Explanation / Answer

The force of gravity is the only force you must counter here.

So the force you need to keep the wheelbarrow parallel to the plank is simply

F = m g sin(39.0)

= 27.90 * 9.8 * sin 39.0

= 1.72 * 10^2 N

= 172. 0 N

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