I need exact answers, please do not waste my time Question Part Points Submissio

Question

I need exact answers, please do not waste my time Question Part Points Submissions Used A bullet of mass 0.017 kg traveling horizontally at a high speed of 200 m/s embeds itself in a block of mass 3 kg that is sitting at rest on a nearly frictionless surface. (a) What is the speed of the block after the bullet embeds itself in the block? vf = m/s (b) Calculate the total translational kinetic energy before and after the collision. Ktrans,i = J Ktrans,f = J

Explanation / Answer

a). 0.017 *200 = (3+0.017) v => v= 1.127 m/s b). K.E. before collision = 0.5*0.017*(200)^2 = 340 J; ; K.E. after collision = 0.5 (3+0.017)(1.127)^2 = 1.916 J

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