A particle with mass 1.71 kg oscillates horizontally at the end of a horizontal

Question

A particle with mass 1.71 kg oscillates horizontally at the end of a horizontal spring. A student measures an amplitude of 0.927 m and a duration of 123 s for 7.0 times 101 cycles of oscillation. Find the frequency, f, the speed at the equilibrium position, v max, the spring constant, k, the potential energy at an endpoint, U max, the potential energy when the particle is located 46.9% of the amplitude away from the equilibrium position, (U and the kinetic energy, K, and the speed, v, at the same position. (Scroll down for more answer blanks.)

Explanation / Answer

a)T=123/70

f=1/T=70/123=0.569Hz

b)vmax=wA=2pi*f*A=3.31m/s

c)f=1/2pi*sqrt(k/m)

k=4pi^2*fm=38.4N/m

d)Umax=0.5kA^2=16.51J

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