Heat is added to an object initially at 30 degrees celcius, increasing its tempe

Question

Heat is added to an object initially at 30 degrees celcius, increasing its temperature to 80 degrees celcius.

A. what is the temperature change in Farenhiet?

I did (9/5)(80-30)+32 = 122 degrees F, but the book says 90 degrees so I'm confused.

B. What is the temperature change in kelvins?

I did 273.15+(80-30) = 323.15 kelvin the book has 50 for the naswer, again confused.

C. Is there any difference in the numerical value of a heat capacity expressed in cal/g*C degrees from one expressed in cal/g*K? Explain.

Explanation / Answer

A)delT in C= 50

(del T)/9|F=(del T)/5|C

(del T)|F=9*50/5 =90

B)(del T)|F=(del T)|C=50

C)no beacause here C---> temperature difference which is same in both cases

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