2. In insects, red eyes (re) and white-banded wings (wb) are encoded by two muta

Question

2. In insects, red eyes (re) and white-banded wings (wb) are encoded by two mutant alleles that are recessive to those that produce wild-type traits (re* and wb); these two genes are on the same chromosome. An insect homozygous for red eyes and white-banded wings is crossed to an insect homozygous for wild-type traits. The F1 have normal eyes and normal wings. The F1 are crossed with insects that have red eyes and white-banded wings in a testcross. The progeny of this test cross are: wild-type eyes, wild type wings red eyes, wild-type wings wild-type eyes, white-banded wings red eyes, white-banded wings 418 19 16 426 2a. Given the data above, what phenotypic proportions would be expected if the genes for red eyes and for white-banded wings were located on different chromosomes? Explain. [5 pts] 2b. What is the percent recombination between the genes for red eyes and those for white-banded wings? [5 pts

Explanation / Answer

2a- Since the gene for eye and wings are linked. So, both the gene will prefer to be together in the next generation. As a result of linkage, we got the given result.

If allele for Wild-type eye and wild-type were on the different chromosome then we would have the following progeny in the following ratio

Wild-type eye -Wild-type Wings: Wild-type eye -white banded wings: red-eye Wild-type-wings: red eye - white banded wings

1:1:1:1.

B - Percentage of recombination is given by a number of recombinant *100/total number of progeny

35*100/879

3.9%

So total number of recombinants are around 3.9%

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