2. In a test tube mix 1 mL of 0.1 M BaCl2 with 1 mL of 0.1 M Na2S0. What happens

Question

2. In a test tube mix 1 mL of 0.1 M BaCl2 with 1 mL of 0.1 M Na2S0. What happens when you mix the two reactants? What does the test tube look like after 3-5 minutes? As part of your observations look-up the solubility of sodium chloride and barium sulfate on the solubility table handout Based on the reactants and the given product what is the formula of the insoluble product you observe in this experiment?

Explanation / Answer

When we mix up BaCl2 and Na2SO4 we get white precipitate of BaSO4 ,and it does not dissolve in HCl. The test tube become white due to precipitation of barium sulphates. In this reaction NaCl and BaSO4 are formed ,NaCl remains dissolved in the aqueous solution, where as Barium sulphate being insoluble in water forms precipitate. Chemical formula of the insoluble product is BaSO4 2) BaCl2 + Na2SO4  -> BaSO4 + 2NaCl Reaction type :- It is a double displacement reaction .Sulphate ions are displaced by chloride ions and vice versa.

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