The force on a positive charge q moving in a magnetic field B^vector with veloci

Question

The force on a positive charge q moving in a magnetic field B^vector with velocity u^vector is F^vector_B = -q u^vector times B^vector. In the set-up shown in Figure 5, the mobile conductor is gray and moves in the positive X- direction in an applied filed B with velocity u which direction is the current flowing in the gray conductor? ii. f the velocity of the conductor is increased in the 2 marks positive x-direction. what will happen to the magnitude of the current? iii. If the magnetic field is applied in the positive x- direction, explain whether there will be an ammeter reading when the conductor moves in the X direction. iv. f the magnetic field is applied in the positive y direction, explain whether there will be an ammeter reading when the conductor moves in the X direction V. f a current I is flowing through the conductor in the positive y-direction the conductor will experience a force F^vector_E acting in which direction?

Explanation / Answer

i- According to left hand thumb rule, the current in the conductor will be in the negative Y direction. Accirding to Left hand thumb rule thumb points in the direction of force, middle finger in the direction of current and first finger in the direction of force.

ii- current will remain constant.

iii- No there will be no flow of current in the ammeter as the filed and force are in the same direction. But according to left hand thumb rule, they should be in perpendicular.

iv- yes there will be a slight movement in the ammeter coil.

V- according to left thumb rule the force will be in negative x direction.

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