I am not understanding this at all. If you could provide the answers and an expl
ID: 2078260 • Letter: I
Question
I am not understanding this at all. If you could provide the answers and an explanation that would be great!
It has been predicted that the gravitational acceleration constant on other planets differs from that on earth. One way to measure this would be to trace the motion of a projectile on that planet and successively calculate velocity and acceleration of the projectile.
3. Procedure:
Take the attached data set which has been collected for the movement of an object on planetary object, Eris. The data reflect the vertical position measured in 0.04 second increments, including the objects position before launch and after capture. Use this data to plot the vertical displacement vs. time, and the velocity vs. time. (two separate graphs). Time should be the x-axis in both plots described below.
At what time was the object launched moving without external influence other than the planet's gravity?
At what time was the object first being recovered/captured?
Plot the vertical position vs. time. When did the object reach its peak/apex?
What type of equation is expected to reflect the movement of the object when unconstrained?
Plot the object’s instantaneous velocity vs time.
From the velocity graph calculate the measured gravitational acceleration for the planet. Provide the uncertainty in the calculated acceleration.
How does this acceleration compare with that on Earth?
Data Set
T
Y
T
Y
0.00
0.5360
1.56
0.8323
0.04
0.5364
1.60
0.7620
0.08
0.5367
1.64
0.6840
0.12
0.5368
1.68
0.6024
0.16
0.5367
1.72
0.5257
0.20
0.5366
1.76
0.4653
0.24
0.5365
1.80
0.4271
0.28
0.5363
1.84
0.4091
0.32
0.5361
1.88
0.4123
0.36
0.5358
1.92
0.4271
0.40
0.5353
1.96
0.4466
0.44
0.5345
2.00
0.4663
0.48
0.5328
2.04
0.4840
0.52
0.5296
2.08
0.4989
0.56
0.5241
2.12
0.5105
0.60
0.5156
2.16
0.5194
0.64
0.5049
2.20
0.5264
0.68
0.4948
2.24
0.5325
0.72
0.4875
2.28
0.5380
0.76
0.4842
2.32
0.5432
0.80
0.4881
2.36
0.5480
0.84
0.5061
2.40
0.5526
0.88
0.5466
2.44
0.5570
0.92
0.6102
2.48
0.5613
0.96
0.6868
2.52
0.5655
1.00
0.7644
2.56
0.5699
1.04
0.8353
2.60
0.5743
1.08
0.8966
2.64
0.5790
1.12
0.9477
2.68
0.5837
1.16
0.9884
2.72
0.5883
1.20
1.0188
2.76
0.5929
1.24
1.0389
2.80
0.5972
1.28
1.0488
2.84
0.6012
1.32
1.0484
2.88
0.6050
1.36
1.0376
2.92
0.6086
1.40
1.0166
2.96
0.6120
1.44
0.9853
3.00
0.6154
1.48
0.9442
1.52
0.8932
T
Y
T
Y
0.00
0.5360
1.56
0.8323
0.04
0.5364
1.60
0.7620
0.08
0.5367
1.64
0.6840
0.12
0.5368
1.68
0.6024
0.16
0.5367
1.72
0.5257
0.20
0.5366
1.76
0.4653
0.24
0.5365
1.80
0.4271
0.28
0.5363
1.84
0.4091
0.32
0.5361
1.88
0.4123
0.36
0.5358
1.92
0.4271
0.40
0.5353
1.96
0.4466
0.44
0.5345
2.00
0.4663
0.48
0.5328
2.04
0.4840
0.52
0.5296
2.08
0.4989
0.56
0.5241
2.12
0.5105
0.60
0.5156
2.16
0.5194
0.64
0.5049
2.20
0.5264
0.68
0.4948
2.24
0.5325
0.72
0.4875
2.28
0.5380
0.76
0.4842
2.32
0.5432
0.80
0.4881
2.36
0.5480
0.84
0.5061
2.40
0.5526
0.88
0.5466
2.44
0.5570
0.92
0.6102
2.48
0.5613
0.96
0.6868
2.52
0.5655
1.00
0.7644
2.56
0.5699
1.04
0.8353
2.60
0.5743
1.08
0.8966
2.64
0.5790
1.12
0.9477
2.68
0.5837
1.16
0.9884
2.72
0.5883
1.20
1.0188
2.76
0.5929
1.24
1.0389
2.80
0.5972
1.28
1.0488
2.84
0.6012
1.32
1.0484
2.88
0.6050
1.36
1.0376
2.92
0.6086
1.40
1.0166
2.96
0.6120
1.44
0.9853
3.00
0.6154
1.48
0.9442
1.52
0.8932
Explanation / Answer
Distance v/s time plot
Velocity v/s time plot
Now acceleration can be given as the slope of velocity time graph
i.e. a = -(1/0.25) = 4m/s2
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