I am not understanding this question. I have the formula fromanother q & a, but

Question

I am not understanding this question. I have the formula fromanother q & a, but i can't understand the components andtherefore can't solve it. Can someone please help? A 1.15kg wooden block has an iron ball of r=1.32 cm glued toone side. If the block floats in water with the iron ball"high and dry" what is the volume of the wood that issubmerged. The formula given to the previous persons question is: mwood+(4/3pi r^2)(pball) / pw I am not understanding this question. I have the formula fromanother q & a, but i can't understand the components andtherefore can't solve it. Can someone please help? A 1.15kg wooden block has an iron ball of r=1.32 cm glued toone side. If the block floats in water with the iron ball"high and dry" what is the volume of the wood that issubmerged. The formula given to the previous persons question is: mwood+(4/3pi r^2)(pball) / pw

Explanation / Answer

I am not understanding this question. I have the formula fromanother q & a, but i can't understand the components andtherefore can't solve it. Can someone please help? A 1.15kg wooden block has an iron ball of r=1.32 cm glued toone side. If the block floats in water with the iron ball"high and dry" what is the volume of the wood that issubmerged. The formula given to the previous persons question is: mwood+(4/3pi r^2)(pball) / pw
let the density of the ball be d now the mass of the ball =4/3 r3d [ r inmeter] [mass of wood+iron ball]*g=volume of the woodsubmerged*density of water*g 1.5+4/3r 3 =volume of woodsubmerged*1000 from this we can calculate volume of woodsubmerged= 1.5+4/3r 3/1000

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