A 3496 D Tue 5:38 PM a E Chrome File Edit View History Bookmarks People Window H

Question

A 3496 D Tue 5:38 PM a E Chrome File Edit View History Bookmarks People Window Help Phoenix College PHY 112 s x C Common Transparent Tape Be x c O www.saplingu /ibiscms/mod/ibis/view.php?id-3142565 Map A Openstax College Physics Po Openstax presented by Sapling Learning Gr What is the force on the charge located at x 16.00 cm in the figure below given that g 1.250 uC? The other two charges are located at 6.000 cm and 22.00 cm. Take the positive direction as pointing to the De right. Pa Number Yo Yo as Yo 24 q yo Th 20.00 10.00 x cm

Explanation / Answer

Here , for the force at -2q

as both other charges will attract the charge -2q

for the net force

net force acting on the -2q charge = force due to q at 22 cm - force due to q at 6 cm

net force acting on the -2q charge = 9 *10^9 * 2 * 1.250 *10^-6 * (1.250 *10^-6/(0.16 - 0.22)^2 - 1.250 *10^-6/(0.16 - 0.06)^2)

net force acting on the -2q charge = 5 N

the net force acting on the -2q charge is 5 N

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