Having trouble with the last portion of the worksheet (except the critical x 2 v
ID: 207581 • Letter: H
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Having trouble with the last portion of the worksheet (except the critical x2 value question). Could someone please help me?
Genetics Chi-square Practice Nar Sec In incomplete dominance alleles of true-breeding (homozygous) parents blend together crossed with white flowers produce a heterozycous F1 generation of pink flowers. A well-studied example . Red flowers humans occurs in the genes for hair. Inheriting a gene for curly hair from one parent and a gene for straight hair from the other parent will give a hair texture that is a blend of the two: wavy hair In codominance alleles of true-breeding (homozygous) parent flowers crossed with white flowers produce a heterozygous F1 generation of flowers that are red wi white spots or white with red spots. A codominant genetic trait in humans occurs with ABO blood types.If someone inherits one A allele and one B allele they will not have a blood type in between those will instead have a blood type AB in which both alleles are expressed s are both expressed in the offspring. Red two but The grid below is another example of Chi-square analysis. This is an example to illustrate incomplete dominance in which neither allele is dominant or recessive. In the example below using snapdragon flowers both parents P1 are true-breeding (homozygous) A plant with red flowers is crossed with a plant with white flowers. The heterozygous F1 generation all have pink flowers. If two pink flowered plants are crossed what will be the phenotypes in the F2 generation? Test your hypothesis by performing a Chi-square analysis What is the expected ratio of red : white: pink phenotypes in the F2 generation? You should draw a Punnett square on the back to work out your hypothesis. Hypothesis: There will bt a phenotyce ratho in the ganerhon Observation of 115 F2 generation plants showed 30 with red flowers, 24 with white flowers, and 61 with pink flowers. Predict the expected number of F2 plants out of 115 that will have red or white or pink flowers Red a8.73 a g,is S7.S Expected (e) Observed (o) Deviation (d = e-o) d squared (d2) d2 divided by e-d2/e . OS Chi-square (X2) value = sum of (d2/e) values-E(d2/e) = Total number of classes Therefore degree of freedom Therefore critical x2 value for p = 0.05 is The calculated x2 value is greater than or less than the critical value (circle one). Therefore the hypothesis is not rejected or rejected (circle the correct conclusion). 61 L.75 3.5 28 I·03 (lab manual page 154) What were the genotypes of the P1 parental generation? andExplanation / Answer
Hypthesis:There will be a 1:2:1 phenotype in the F1 generatiion
Red White Pink
Expected(e) 28.75 28.75 57.5
Observed(o) 30 24 61
Deviation(d=e-o) -1.25 4.75 -3.5
d squared (d2) 1.5625 22.5625 12.25
d2 divided by e =d2/e .05 .78 .2
Chi-square(×2) value =sum od d2 values= 1.03
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