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A solenoid with 500 turns, 0.10 m long, carrying a current of 4.0A and with a ra

ID: 2075492 • Letter: A

Question

A solenoid with 500 turns, 0.10 m long, carrying a current of 4.0A and with a radius of 1.0 cm. a) What is strength magnetic field at its center? (magnetic permeability in empty space mu_0 = 4 pi times 10^-7 T times m/A) (2.50 times 10^-2 T) b) what is total length of the wire? A uniform 4.5 T magnetic field passes through the plane of a wire loop 0.10 m^2 in area. What flux passes through the loop when the direction of the 4.5 T field is at a 30 degree angle to the normal of the loop plane? (0.39 T times m^2) A flat coil of wire consisting of 20 turns, each with an area of 50 cm^2 is positioned perpendicularly to a uniform magnetic field that increases its magnitude at a constant rate from 2.0 T to 6.0 T in 2.0 s. If the coil has a total resistance of 0.40 W, what is the magnitude of the induced current? (0.50 A) What is the minimum frequency with which a 200 turn, flat coil of cross sectional area 300 cm^2 can be rotated in a uniform 30 mT magnetic field if the maximum value of the induced emf is to 8.0 v? (7.1 Hz) What is the self-inductance in a coil that experiences a 3.0 V induced emf when the current is changing at a rate of 110 A/s? (27 mH) A 12 V battery is connected in series with a switch, resistor and coil. If the circuit's time constant is 2.0 times 10^-4 s and the final steady current after the switch is closed becomes 1.0 A, what is the value of the inductance? (2.4 mH) For a circuit shown n figure determine the current and power in each resistor.

Explanation / Answer

(15). Magnitude of self inductance, E = L (di/dt) ---------( 1)

Where L = self inductance

di / dt = rate of change of current = 110 A/s

Given E = 3.0 V

From equation (1), L = E /(di/dt)

= 3V /(110A/s)

= 27.27x10 -3 H

= 27.27 mH

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