A 9.50 10-3 kg bullet is fired horizontally into a 2.39 kg wooden block attached

Question

A 9.50 10-3 kg bullet is fired horizontally into a 2.39 kg wooden block attached to one end of a massless, horizontal spring (k = 841 N/m). The other end of the spring is fixed in place, and the spring is unstrained initially. The block rests on a horizontal, frictionless surface. The bullet strikes the block perpendicularly and quickly comes to a halt with in it. As a result of this completely inelastic collision, the spring is compressed along its axis and causes the block/bullet to oscillate with an amplitude of 0.200 m. What is the speed of the bullet?

Explanation / Answer

Given A 9.50 10-3 kg bullet is fired horizontally into a 2.39 kg wooden block attached to one end of a massless, horizontal spring (k = 841 N/m).The spring is compressed along its axis and causes the block/bullet to oscillate with an amplitude of 0.200 m.

By conservation of energy K.E of block = P.E of the spring

m*V^2 = K*x^2

9.5 *10-3 V^2 = 841*0.04

V = 59.5m/s

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