A.) Determine the image position. B.) Determine the magnification. Both images a

Question

A.) Determine the image position.

B.) Determine the magnification.

Both images are real. The image of the first object is real and the image of the second object is virtual. The image of the first object is virtual and the image of the second object is real. Both images are virtual. A converging lens has a focal length of 15.0 cm. For each of two objects located to the left of the lens, one at a distance of s1 = 23.0 cm and the other at a distance of s2 = 5.00 cm. A.) Determine the image position. s1',s2' =? B.) Determine the magnification. m1,m2 =? C.) whether the image is real or virtual. You only have to choose 1 of these answers for part C.) Both images are real. The image of the first object is real and the image of the second object is virtual. The image of the first object is virtual and the image of the second object is real. Both images are virtual. D.)whether the image is erect or inverted. You only have to choose 1 of these answers for part D.) Both images are erect. The image of the first object is erect and the image of the second object is inverted. The image of the first object is inverted and the image of the second object is erect. Both images are inverted.

Explanation / Answer

for converging lens i/f =1/u +1/v 1/v = 1/f -1/u v = uf/u-f a) for object at 23 cm, v = 23*15/8 v = 43.125cm B) for object at 5 cm v = 15*5/10 = v = 7.5 cm m = -v/u = 43.125/23 m= 1.75 m = 7.5/5 =1.5 C) Both images are real. D) both images are inverted

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