A.) A ship is anchored off a long straight shoreline that runs north and south.

Question

A.) A ship is anchored off a long straight shoreline that runs north and south. From two observation points 16 miles apart on shore, the bearings of the ship are N 35° E and S 59°E. What is the distance from the ship to each of the observation points? (Round your answers to one decimal place.)

distance from southern point mi

B.)If you have ever ridden on a chair lift at a ski area and had it stop, you know that the chair will pull down on the cable,

dropping you down to a lower height

than when the chair is in motion. The figure shows a gondola that is stopped. Find the magnitude of the tension

in the cable toward each end of the cable if the total weight of the gondola and its occupants is 1,830 pounds.

Assume E = 67.8° and F = 76.8°. (Round each answer to the nearest whole number.)

|CB| =  lb

|CA| =  lb

distance from southern point mi

B.)If you have ever ridden on a chair lift at a ski area and had it stop, you know that the chair will pull down on the cable,

dropping you down to a lower height

than when the chair is in motion. The figure shows a gondola that is stopped. Find the magnitude of the tension

in the cable toward each end of the cable if the total weight of the gondola and its occupants is 1,830 pounds.

Assume E = 67.8° and F = 76.8°. (Round each answer to the nearest whole number.)

|CB| =  lb

|CA| =  lb

Explanation / Answer

B) We Let tension in CA = a and CB=b

Lets find the x and y components of the tension

X dierection : a*sin67.8 = bsin76.8 ; 0.92a =0.97b ---(1)

Y direction : acos67.8 +bcos76.8 = 1830 pounds -----(2)

Solve the two equations: 0.377a + 0.228b = 1830

a = 1.05b

So, a =1830/0.6254 =2926 lb ---CA

b = 2786.78 = 2787 lb------ CB

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