L-C Oscillations. A Capacitor with a capacitance of 6.03x10^-5 F is charged by c
ID: 2067981 • Letter: L
Question
L-C Oscillations. A Capacitor with a capacitance of 6.03x10^-5 F is charged by connecting it to a battery which provides an emf of 12.4 V. The capacitor is then disconnected from the battery and connected across an inductor with an inductance of 1.54 H.A) At the time given (2.29x10^-2 seconds), what is the current in the inductor?
B) At the time given (2.29x10^-2 seconds), how much electrical energy is stored in the capacitor?
C) At the time given in part (2.29x10^-2 seconds), how much electrical energy is stored in the inductor?
Explanation / Answer
for LC ckt, Im = qm0
and capacitance C=Q/V
Q= CV
Q = 6.03*10^-5*12.4
= 74.7 C
Im = q0/LC
= 74.4/(1.54*6.03*10^-5)
im = 7720 amps
B) U = CV^2/2
= 6.03*12.4*12.4/2
463 .5 JOULES
c) U in inductor = Li^2/2
= 1.54*7720*7720/2
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