L Determination of the Yield of KCI Observations Appearance of KCIOWHITE, PewIS

Question

L Determination of the Yield of KCI Observations Appearance of KCIOWHITE, PewIS Appearance of KCI product-whUTE.eoree- Data and Results Mass of 250 mL flask, ignition tube and KCIO Mass of 250 mL flask and ignition tube Mass of KCIO, used Mass of 250 mL flask, ignition tube and KCl product Mass of KCI product Moles of KCIO, used (SHOW WORK BELOw) Theoretical yield of KCI (SHOW WORK BELOW) Percent yield of KCI (SHOW WORK BELOW 170 S44 0.432 71.036 7669 moles Calculations: (SHOW WORK HERE) Moles KCIO, used Theoretical yield of KC %yield of KCI Ext. 24 24-11 Gas Stoichiometry

Explanation / Answer

moles of KClO3

mas sof KClO3 used = 0.432 g

MW of KClO3 = 122.55 g/mol

mol = masS/MW = 0.432/122.55 = 0.0035250 mol of KClo3

b)

theoretical yield of KCl

1 mol of KCl is inside 1 mol of KClO3

so yield should be 0.0035250 mol o fKClo3

mass = mol*MW = 0.0035250*74.5513 = 0.26279 g of KCl

now..

your measuremnt of KCl --> (171.3036-170.544) = 0.3276

% Yield = mass of KCl obtained / theoretical mass * 100%

% Yield = 0.266 /0.26279 * 100% = 101%

which is impossible, since there is no creation of mass, this should have an error

most likely error --> not all KClO3 converted to KCl

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