(a) A 25 O resistor is connected in series with a 7 µF capacitor and a battery.

Question

(a) A 25 O resistor is connected in series with a 7 µF capacitor and a battery. What is the maximum charge to which this capacitor can be charged when the battery voltage is 9 V?




(b) Initially the capacitor has zero charge. At what time during the charging process will the charge on this capacitor be 39.8 µC?




(c) The capacitor is now fully charged. The battery is removed and the capacitor is discharged through a bulb. What will be the charge on the capacitor after 0.175 ms? (Assume that the bulb has the same resistance as the original resistor.)

Explanation / Answer

(a) maximum charge to which capacitor can be charged (q) = C*V = 63 C

(b) Voltage at time t is given by

V(t) = V0 * (1 - e-t/RC )

cahrge at time t is

Q(t) = Q0 * (1 - e-t/RC)

substituting Q0 = 63 C, R = 25 , C = 7F, Q(t) = 39.8 C,

we get t = 174.82 s

(c) During discharging,

Q(t) = Q0 * (e-t/RC)

substituting Q0 = 63 C, R = 50 , C = 7F, t = 0.175ms

Q(t) = 38.211 C

PLEASE DO RATE ME LIFESAVER

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