A.) Starting from rest, a car goes 15 meters to reach a velocity \"v\" at consta

Question

A.) Starting from rest, a car goes 15 meters to reach a velocity "v" at constant acceleration. How many additional meters are required to reach an velocity of "5v"?

B.) A 1.05-kg wooden block rests on a table over a large hole as in the figure below. A 3.10-g bullet with an initial velocity vi is fired upward into the bottom of the block and remains in the block after the collision. The block and bullet rise to a maximum height of 16.0 cm. Calculate the initial velocity of the bullet from the information provided. (Let up be the positive direction.)

Explanation / Answer

v^2-u^2 = 2as acceleration is same. so, s is directly proportional to v^2 so, to reach a velocity 5v, s = 25*15 = 375 m Post the second question in another post and I shall answer it Thank you

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