a)You operate a small grain elevator near Champaign, Illinois. One of your silos

Question

a)You operate a small grain elevator near Champaign, Illinois. One of your silos uses a bucket elevator that carries a full load of 800 kg through a vertical distance of 40 m. (A bucket elevator works with a continuous belt, like a conveyor belt.) (a) What is the power provided by the electric motor powering the bucket elevator when the bucket elevator ascends with a full load at a speed of 2.3 m/s?
b) Assuming the motor is 85 percent efficient, how much does it cost you to run this elevator, per day, assuming it runs 60 percent of the time between 7:00 a.m. and 7:00 p.m. with an average load of 85 percent of a full load? Assume the cost of electric energy in your location is 15 cents per kilowatt hour

Explanation / Answer

a) Power = work/time

work done = 800*9.8*40 (mgh)

time = 40/2.3

Power = 800*9.8*40/(40/2.3) = 18032 W

b) Cost = 0.15*(.85)*(12*60*60*0.6)(.85*18.032) = 50653.33 cent or $506.53

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