5. A parallel-plate capacitor has a plate separation of 5.0 cm. If the potential

Question

5. A parallel-plate capacitor has a plate separation of 5.0 cm. If the potential difference between the plates is 2000 V, with the top plate at the higher potential, what is the electric field between
the plates?

6) Two parallel plates, separated by 0.20 m, are connected to a 12-V battery. An electron released from rest at a location 0.10 m from the negative plate. When the electron arrives at a distance 0.050 m from the positive plate, what is the speed of the electron?

8. Electric field lines near positive point charges
A) circle clockwise. B) circle counter-clockwise.
C) radiate inward. D) radiate outward.

Explanation / Answer

5) V = Ed => E = V/d = 2000/(0.05) = 40,000 N/C 6) Electric field = V/d = 12/0.2 = 24 N/C Using conservation of energy W by Elec field = Change in KE 24 x ( 0.10 - 0.05) = m(v^2)/2 v = 1.624 x 10^15 m/s. 7) By definition of Electric field lines radiate outward of Positive charges and radiate into Negative charges

Related Questions

Navigate

• Browse (All)
• Browse 5
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.