An electron and a proton move in circular orbits in a plane perpendicular to a u

Question

An electron and a proton move in circular orbits in a plane perpendicular to a uniform magnetic field Barrowbold.
(a) Find the ratio of the radii of their circular orbits when the electron and the proton have the same kinetic energy.
re/rp = 1 Incorrect: Your answer is incorrect.
Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully.
answer not 1!

(b) Find the ratio of the radii of their circular orbits when the electron and the proton have the same momentum.


re/rp =

answer not 0.02

Explanation / Answer

qvB = mv^2/r r = mv/qB when same KE v(proton) = sqrt(2K/Mp) v(electron) = sqrt(2K/Me) so re = Me*sqrt(2K/Me) / eB rp = Mp*sqrt(2K/Me) / eB dividing we get re/rp = sqrt(Me/Mp) = .0233 when same momentum Vp = P/Mp Ve = P/Me so re = (Me*P/Me)/ eB rp = (Mp*P/Mp)/ eB re/rp = 1

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