A horizontal rod 0.230 m long carries a current through a uniform horizontal mag

Question

A horizontal rod 0.230 m long carries a current through a uniform horizontal magnetic field of magnitude 6.80×102 T that points perpendicular to the rod.

Could you please show me the step by steps for how to solve this problem? Thanks!!! :)

A horizontal rod 0.230 m long carries a current through a uniform horizontal magnetic field of magnitude 6.8010-2 T that points perpendicular to the rod. 1.If the magnetic force on this rod is measured to be 0.180 N, what is the current flowing through the rod? [I = A] Could you please show me the step by steps for how to solve this problem? Thanks!!! :)

Explanation / Answer

Force acting on a current carrying rod = (current in rod)*(Length of the rod)*(Magnetic field) { This is the basic formula for finding the force on a current carrying wire/rod in magnetic field } Let current flowing be i so .18 = i*.23*6.8*10^-2 so solving for i we get i = 11.508 A

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