Two charges, q1= 4.0 µC and q2= -2.0 µC, are located at two corners of an equila

Question

Two charges, q1= 4.0 µC and q2= -2.0 µC, are located at two corners of an equilateral triangle of side a= 10 cm as shown below.

a) Calculate the net electric field (magnitude and direction) created by these two charges at the other corner of the triangle (point P).

b) What is the electric potential at point P?

C) If a proton is released from point P from rest, what would be its speed when it reaches infinity? Assume no energy loss.

Two charges, q1= 4.0 MuC and q2= -2.0 MuC, are located at two corners of an equilateral triangle of side a= 10 cm as shown below. a) Calculate the net electric field (magnitude and direction) created by these two charges at the other corner of the triangle (point P). b) What is the electric potential at point P? C) If a proton is released from point P from rest, what would be its speed when it reaches infinity? Assume no energy loss.

Explanation / Answer

a)

k = 8.998e9

Ex = k* ((-2e-6/0.01)*cos(60) + (4e-6/0.01)) = 2.699e6 N/C

Ey = k*(-2e-6/0.01)*sin(60) = -1.558e6 N/C

E = (Ex^2 + Ey^2)

E = 3.117 x 10^6 N/C

direction = arctan(Ey/Ex) = -30 degrees = -/6 radians

b)

V = k*(-2e6/0.1 + 4e6/0.1)

V = 1.8 x 10^17 V

c)

V*q = 0.5*m*vel*vel

q = 1.6e-19

m = 1.67e-27

so,

velocity,v = 5.872 x 10^12 m/s

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