<p>A horizontal rectangular surface has dimensions 3.10 cm by 3.15 cm and is in

Question

<p>A horizontal rectangular surface has dimensions 3.10 cm by 3.15 cm and is in a uniform magnetic field that is directed at an angle of 28.0 degrees above the horizontal.</p>
<div class="partText">What must the magnitude of the magnetic field be in order to produce a flux of <span>4.10&#215;10^&#8722;4</span>&#160;<img src="http://session.masteringphysics.com/render?units=Wb" alt="Wb" align="middle" /> through the surface?</div>

Explanation / Answer

Flux is found by BAcos where is the angle between the mag field and the area VECTOR.

For a horizontal rectangular surfcae, the area vector points UP ( or down, whichever ). So if the mag field is 28 above the horizontal, and the angle we need is with respect to the area vector ( up ) then we need

90 - 28 = 62 degrees.

Now, to plug in:

= BAcos

4.1e-4 = B( .0310 X .0315 )cos62

B = 0.894 T

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