a) Where will the final image be located? in cm (image will be on left) b) The i

Question

a) Where will the final image be located? in cm (image will be on left)

b) The intermediate image from the converging lens serves as an object for the diverging lens. What kind of object is it? real or virtual?

Explanation / Answer

a) first image,v1 : 1/v1 = 1/f1 + 1/u1 v1 = 46.94 cm it acts as an object for the diverging lens. => u2 = 46.94-12 = 34.94 cm => v2 = -23.36cm from second lens = 23.36 cm left of second lens(diverging) = 11.36 cm left of first lens(converging) b) Intermediate image is formed right of diverging lens. No real object could be right of a lens. => Object is virtual. c) in that case, u2 = 46.94 - 45 = 1.94 cm v2 = 2.25 cm right of diverging lens = 47.25 cm right of converging lens.

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.